ACtE05 · Chapter 5Networks & Security🏛️ Past Licensure QuestionID: 2dd4a3c2
Let two machines be P and Q. The state in which P can simulate Q and Q can simulate P is called:
Let two machines be P and Q. The state in which P can simulate Q and Q can simulate P is called:
Multiple Choice Options
- A✓ Correct Option
Turing Equivalence
- B
State Equivalence
- C
Universal Turing machine
- D
None of the mentioned
Detailed Technical Solution & Explanation
According to standard engineering principles, for Let two machines be P and Q. The state in which P can simulate Q and Q can simulate P is called:, the correct choice is Turing Equivalence.
Option Analysis:
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Option A (Turing Equivalence): Correct. Valid technical statement directly addressing the question requirement.
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Option B (State Equivalence): Incorrect. Does not satisfy the technical condition or specifies an alternate/invalid property.
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Option C (Universal Turing machine): Incorrect. Does not satisfy the technical condition or specifies an alternate/invalid property.
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Option D (None of the mentioned): Incorrect. Does not satisfy the technical condition or specifies an alternate/invalid property.
Reference: Mock Test 04NEC Licensure Syllabus