ACtE08 · Chapter 8Mock Test 02🏛️ Past Licensure QuestionID: 4a95390d

The resonant frequency of a parallel resonant bandpass filter is 20 kHz and its bandwidth is 2 kHz. Its upper cutoff frequency is:

Multiple Choice Options

A
18 kHz
B
19 kHz
C
21 kHz
✓ Correct Option
D
22 kHz

Detailed Technical Solution & Explanation

For a symmetrical bandpass filter, the resonant (center) frequency $f_0$ is located midway between the lower cutoff frequency $f_L$ and upper cutoff frequency $f_H$ :

BW = f_H - f_L

f_H = f_0 + \frac{BW}{2}

f_L = f_0 - \frac{BW}{2}

Given $f_0 = 20\text{ kHz}$ and $BW = 2\text{ kHz}$ :

f_H = 20\text{ kHz} + \frac{2\text{ kHz}}{2} = 20 + 1 = 21\text{ kHz}

f_L = 20\text{ kHz} - 1\text{ kHz} = 19\text{ kHz}

Option Analysis:

•

Option A (18 kHz): Incorrect;

20 - 2 = 18\text{ kHz}

, which subtracts the full bandwidth.

•

Option B (19 kHz): Incorrect; this is the lower cutoff frequency (

f_L

•

Option C (21 kHz): Correct; upper cutoff frequency

f_H = 20 + 1 = 21\text{ kHz}

•

Option D (22 kHz): Incorrect;

20 + 2 = 22\text{ kHz}

, which erroneously adds the full bandwidth.

Reference: Mock Test 02NEC Licensure Syllabus

The resonant frequency of a parallel resonant bandpass filter is 20 kHz and its bandwidth is 2 kHz. Its upper cutoff frequency is:

Multiple Choice Options

Detailed Technical Solution & Explanation

Option Analysis:

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The resonant frequency of a parallel resonant bandpass filter is 20 kHz and its bandwidth is 2 kHz. Its upper cutoff frequency is:

Multiple Choice Options

Detailed Technical Solution & Explanation

Option Analysis:

Want to practice this topic interactively?